if a force of 10N acts on surfaces of areas in ratio 1 : 2,then what is the ratio of thrusts

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Solution

1. Force = 10 N

Area (1) = x
Area (2) = 2x

2. Thrust (1) = $\frac{F o r c e}{A r e a (1)} = \frac{10}{x}$
Thrust (2) = $\frac{F o r c e}{A r e a (2)} = \frac{10}{2 x}$

3. Ratio :

$\frac{T h r u s t (1)}{T h r u s t (2)} = \frac{\frac{10}{x}}{\frac{10}{2 x}} = 2 : 1$

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Q. If a force of 10 N acts on two surfaces of areas in the ratio 1 : 2, then the thrust on them has the ratio

Q. A force of 100N acts on the surface of area 10cm2 normally. What are the thrust and pressure on the surface?

Q. Assertion :The pressure at a point is the ratio of force to the area on which force is acting. Reason: Pressure is the thrust acting per unit area.

Statement 1: For the same load/force acting on two different surfaces, more pressure is developed on the surface with a smaller area.
Statement 2: Pressure is defined as thrust(force acting normally to the surface) per unit area.

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if a force of 10N acts on surfaces of areas in ratio 1 : 2,then what is the ratio of thrusts

1. Force = 10 N Area (1) = x Area (2) = 2x 2. Thrust (1) = ForceArea (1)=10x Thrust (2) = ForceArea (2)=102x 3. Ratio : Thrust (1)Thrust (2)=10x102x=2:1

1. Force = 10 N

Area (1) = x
Area (2) = 2x

2. Thrust (1) = $\frac{F o r c e}{A r e a (1)} = \frac{10}{x}$
Thrust (2) = $\frac{F o r c e}{A r e a (2)} = \frac{10}{2 x}$

3. Ratio :

$\frac{T h r u s t (1)}{T h r u s t (2)} = \frac{\frac{10}{x}}{\frac{10}{2 x}} = 2 : 1$