If a force of 4N is applied on a body of mass 20kg, then the work done in 3rd second will be
A
1.2J
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B
2J
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C
4J
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D
16J
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Solution
The correct option is C2J Here, a=fm=420=15m/s2 Distance travelled by by body in 3rd second S3rd=0+15×2(2×3−1)=0.5m Hence, work done, W=f×S3rd=4×0.5=2J.