The correct options are
A Image of 2 under f is 4
B Image of 5 under f is 10
D Preimage of 6 under f is 3
Here, function is defined from A to B
f(1)=2
f(2)=4
f(3)=6
f(4)=8
f(5)=10
Image of 2 under f is 4
Image of 5 under f is 10
Preimage of 4 under f is 2
Preimage of 6 under f is 3