If a function 'f' defined by f(x) = 2x + 3, then find the value of 'x' such that f(x) = f(1-x).

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\frac{1}{2}

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- \frac{1}{2}

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Solution

The correct option is B $\frac{1}{2}$
Given, f(x) = 2x + 3
$∴$ f(1-x) = 2(1-x) + 3
= 5 - 2x
Now, f(x) = f(1-x)
$\Rightarrow$ 2x + 3 = 5 - 2x
$\Rightarrow$ 4x = 2
$\Rightarrow$ x = $\frac{1}{2}$

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If a function 'f' defined by f(x) = 2x + 3, then find the value of 'x' such that f(x) = f(1-x).

The correct option is B 12Given, f(x) = 2x + 3 ∴ f(1-x) = 2(1-x) + 3 = 5 - 2x Now, f(x) = f(1-x) ⇒ 2x + 3 = 5 - 2x ⇒ 4x = 2 ⇒ x = 12

The correct option is B $\frac{1}{2}$
Given, f(x) = 2x + 3
$∴$ f(1-x) = 2(1-x) + 3
= 5 - 2x
Now, f(x) = f(1-x)
$\Rightarrow$ 2x + 3 = 5 - 2x
$\Rightarrow$ 4x = 2
$\Rightarrow$ x = $\frac{1}{2}$