wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If A,G and H are respectively arithmetic, geometric and harmonic means between a and b both being unequal and positive, then A=a+b2a+b=2A,G=abab=G2 and H=2aba+bG2=AH
From the above discussion we can say that a,b are the roots of the equation x22Ax+G2=0
Now,quadratic equation, x2Px+Q=0 and quadratic equation a(bc)x2+b(ca)x+c(ab)=0 have a root common and satisfy the relation b=2aca+c, where a,b,c are real numbers.
On the basis of the above information, answer the following questions:
The ratio of A.M, G.M and H.M of the roots of the given quadratic equation is:

A
1:2:3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1:1:2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2:2:3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1:1:1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 1:1:1
Given: a(bc)x2+b(ca)x+c(ab)=0 .......(1)
a(bc)+b(ca)+c(ab)=abac+bcba+cacb=0
x=1 is a root of eqn(1)
Let the other root be α then 1×α=c(a2aca+c)a(2aca+cc) b=2aca+c
On evaluating,we get the other root as =ca2+c2a2ac22a2ca2cc2a=ca2ac2ca2ac2=ac(ac)ac(ac)=1
Hence both the roots of eqn(1) are 1,1
Then roots of the equation x2Px+Q=0 is also 1,1
A.M=G.M=H.M
That is a+b2=ab=2aba+b
Hence A.M:G.M:H.M=1:1:1

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Arithmetic Progression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon