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Question
If a gas at 10 atm and 300 K expands against a constant external pressure of 2 atm from a volume of 10 litres to 20 litres, the amount of work done is:
Given: 1 L.atm = 101.3 J
If a gas at 10 atm and 300 K expands against a constant external pressure of 2 atm from a volume of 10 litres to 20 litres, the amount of work done is:
Given: 1 L.atm = 101.3 J
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Solution
The correct option is C −2026 J
As the process is done at a constant external pressure, it is irreversible.
W=−∫2010P.dV=−∫20102dV
⇒ W=−2[20−10]
⇒ W=−20 L.atm
As, 1 L.atm = 101.3 J
i.e W=−20×101.3 J=−2026 J
As the process is done at a constant external pressure, it is irreversible.
W=−∫2010P.dV=−∫20102dV
⇒ W=−2[20−10]
⇒ W=−20 L.atm
As, 1 L.atm = 101.3 J
i.e W=−20×101.3 J=−2026 J
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