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Question

If a gas expands irreversibly from 5 L to 10 L against a pressure of 3 atm, then work done will be nearly:

A
-15 J
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B
+15 J
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C
-1520 J
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D
+1520 J
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Solution

The correct option is C -1520 J

When the gas expands, system does work on surroundings so work done will be negative
W = -P (V2V1)
given P= 3 atm = 3×101325Pa =303975 Pa
V2= 10 L = 10×103m3 , V1= 5 L = 5×103m3
W = -303975 ×(105)×103
= -1519.875 J -1520 J


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