Question

If a gas has $RMS$ velocity $5.2\times {10}^{4}cm/s$. Find the average and M.P velocity of the gas.

Answer 1

$\text{Given, RMS Velocity = 5.2}\times {10}^{4}cm/s\text{Relation between average, most probable and RMS Velocity is}{V}_{mp}:V_{avg}:V_{rms}=1.414:1.596:1.732=1:1.128:1.224\Rightarrow \frac{V_{mp}}{V_{rms}}=\frac{1}{1.224}\Rightarrow V_{mp}=4.248\times {10}^{4}cm/s\Rightarrow \frac{V_{avg}}{V_{rms}}=\frac{1.128}{1.224}\Rightarrow V_{avg}=4.792\times {10}^{4}cm/s$