Question

If a gene from haemolytic jaundice is dominant and 10% population carrying this gene develops disease then, what percentage of progeny from a marriage between heterozygous for haemolytic jaundice and normal individual suffers from this disease?

1. 50%
2. 5%
3. 10%
4. 1/5th

Answer 1

Dear student,
Answer is 2) 5%
Haemolytic jaundice is caused by dominant allele. Since 10% of the population is carrying the disease. Marriage between heterozygous male (Aa) and normal woman (aa). The cross between Aa and aa results in 50% Aa and 50% aa. 50% of the progeny will be suffering from haemolytic jaundice. Since 10% of the population is carrying the disease therefore 10% of 50% will be 5%. So 5% of the progeny will be suffering from haemolytic jaundice.

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