If A has 5 elements and B has 8 elements such that A- B- then the number of elements in A- B- and A- B- are respectively -

The correct option is C 5, 8Since A⊂ B , A∩ B will be all the elements of A. So, the number of elements will be 5.Since A⊂ B , A∪ nbsp;B ...

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Standard XII

Mathematics

De Morgan's Law

If A has 5 el...

Question

If A has 5 elements and B has 8 elements such that $A \subset B,$ then the number of elements in $A \cap B,$ and $A \cup B,$ are respectively :

8 , 5

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3 , 3

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5, 8

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5, 13

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Solution

The correct option is C 5, 8
Since $A \subset B$ , $A \cap B$ will be all the elements of A. So, the number of elements will be 5.
Since $A \subset B$ , $A \cup B$ will be all the elements of A & B. So, the number of elements will be 8.

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If A has 5 elements and B has 8 elements such that A⊂B, then the number of elements in A∩B, and A∪B, are respectively :

The correct option is C 5, 8Since A⊂B, A∩B will be all the elements of A. So, the number of elements will be 5.Since A⊂B, A∪B will be all the elements of A & B. So, the number of elements will be 8.

If A has 5 elements and B has 8 elements such that $A \subset B,$ then the number of elements in $A \cap B,$ and $A \cup B,$ are respectively :

The correct option is C 5, 8
Since $A \subset B$ , $A \cap B$ will be all the elements of A. So, the number of elements will be 5.
Since $A \subset B$ , $A \cup B$ will be all the elements of A & B. So, the number of elements will be 8.