If a heater of resistance 100Ω draws a current of 5A for 1hour, then the energy consumed by the heater is:
A
3600kJ
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B
9000kJ
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C
2500kJ
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D
1800kJ
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Solution
The correct option is B9000kJ Given: Resistance (R)=100Ω Current (I)=5A Time (t)=1hour=3600s
According to joule's law of heating, heat generated is given by: H=I2Rt=(5A)2×100Ω×3600s =9000000J=9000KJ Therefore, the energy consumed by the heater is 9000KJ.