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Question

If a heater of resistance 100 Ω draws a current of 5 A for 1 hour, then the energy consumed by the heater is:

A
3600 kJ
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B
9000 kJ
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C
2500 kJ
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D
1800 kJ
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Solution

The correct option is B 9000 kJ
Given:
Resistance (R)=100 Ω
Current (I)=5 A
Time (t)=1 hour=3600 s

According to joule's law of heating, heat generated is given by: H=I2Rt=(5A)2×100Ω×3600s
=9000000 J=9000 KJ
Therefore, the energy consumed by the heater is 9000 KJ.

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