Question

If a homogeneous catalytic reaction follows three alternative paths $A$, $B$ and $C$, then which of the following indicates the relative ease with which the reaction moves?

• A. $A>B>C$
• B. $C>B>A$
• C. $A>C>B$
• D. $A=B=C$

Answer 1

The correct option is B $C>B>A$

Lower the activation energy for a path, more will be the ease with which the reaction moves. In the given graph, the order of activation energy is $A>B>C$.

Hence, the ease with which the reaction moves has the order: $C>B>A$.