If a hydrocarbon has 5 carbon skeletal and there is a double bond between the $2^{n d}$ and the $3^{r d}$ carbon, what is it named as?

But-2-ene

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Hept-3-ene

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Pent-2-ene

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Pent-3-ene

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Solution

The correct option is C Pent-2-ene
While naming unsaturated compounds, we consider the number of the least value as the position of the double bond. So the hydrocarbon with 5 carbon skeletal with a double bond positioned at 2 is Pent-2-ene.

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Similar questions

2^{n d}

3^{r d}

A hydrocarbon with 5 carbons and there is a double bond between the $2^{n d}$ and the $3^{r d}$ carbons, what is it named as?

2^{n d}

3^{r d}

2^{n d}

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