If a hyperbola has length of its conjugate axis equal to 5 unit and the distance between its foci is 13 unit, then the eccentricity of the hyperbola is
A
136
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B
2
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C
138
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D
1312
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Solution
The correct option is D1312 Let equation of the hyperbola is x2a2−y2b2=1
According to question, 2b=5⇒b=52
and 2ae=13⇒ae=132