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Question

If Ai=[aibibiai] and |a|<1,|b|<1 then i=1|Ai| is equal to

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Solution

|A|i=aibibiai=a2ib2i
i=1|Ai|=(a2b2)+(a4b4)+(a6b6)+....
=(a2+a4+a6+....)(b2+b4+b6+...)
=a21a2b21b2
=a2b2(1a2)(1b2)

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