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Byju's Answer
Standard XII
Mathematics
Logarithmic Function
If Ai=x-ai/...
Question
If
A
i
=
x
−
a
i
|
x
−
a
i
|
where
i
=
1
,
2
,
3
and
a
1
<
a
2
<
a
3
then
lim
x
→
a
2
A
1
A
2
A
3
=
A
−
1
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B
1
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C
0
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D
does not exist
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Solution
The correct option is
C
does not exist
The question asks us about,
lim
x
→
a
2
x
−
a
1
|
x
−
a
1
|
×
x
−
a
2
|
x
−
a
2
|
×
x
−
a
3
|
x
−
a
3
|
Now, since
lim
x
→
a
2
x
−
a
2
|
x
−
a
2
|
does not exist because
lim
x
→
a
2
−
x
−
a
2
|
x
−
a
2
|
=
−
1
lim
x
→
a
2
+
x
−
a
2
|
x
−
a
2
|
=
1
Since, LHL is not equal to RHL , hence the limit does not exist.
Therefore, the limit of the entire function does not exist
Suggest Corrections
0
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Q.
A
i
=
x
−
a
i
|
x
−
a
i
|
,
i
=
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,
2
,
.
.
.
.
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,
n
,
and
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<
a
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<
a
3
<
.
.
.
.
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If
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,
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=
lim
x
→
a
+
m
(
A
1
A
2
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.
.
.
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n
)
is
Q.
Let
a
1
,
a
2
,
a
3
,
…
,
a
n
be the integers which are not included in the range of
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(
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)
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where
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i
>
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for each
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1
,
2
,
3
,
…
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n
. If
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∑
i
=
1
5
−
a
i
C
i
−
1
=
x
C
y
, then
x
+
y
can be
Q.
Let
a
1
=
0
and
a
1
,
a
2
,
a
3
, ...,
a
n
be real numbers such that
|
a
i
|
=
|
a
i
−
1
+
1
|
for all i then the AM of the numbers
a
1
,
a
2
,
a
3
, ...,
a
n
has the value A where
Q.
If
A
i
is the area bounded by
|
x
−
a
i
|
+
|
y
|
=
b
i
,
where
a
i
+
1
=
a
i
+
3
2
b
i
and
b
i
+
1
=
b
i
2
;
a
1
=
0
,
b
1
=
32
,
then
Q.
If
A
i
is the area bounded by
|
x
−
a
i
|
+
|
y
|
=
b
i
,
i
∈
N
,
where
a
i
+
1
=
a
i
+
3
2
b
i
and
b
i
+
1
=
b
i
2
,
a
1
=
0
,
b
1
=
32
,
then
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