If a -ii-j- and b -j-2 k- find a -2 b - a -b -

We #160;havea #8594;=i #8743; j #8743; #160;and #160;b #8594;= j #8743;+2k #8743;a #8594; 2b #8594;=i #8743; j #8743; #160; 2 #160 ...

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Properties of Determinants

If a →=ii-j∧ ...

Question

$If \vec{a} = \hat{i} - \hat{j} and \vec{b} = - \hat{j} + 2 \hat{k}, find (\vec{a} - 2 \vec{b}) \cdot (\vec{a} + \vec{b}) .$

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\vec{a} \cdot \vec{b}

\vec{a} = \hat{i} - 2 \hat{j} + \hat{k} and \vec{b} = 4 \hat{i} - 4 \hat{j} + 7 \hat{k}

\vec{a} = \hat{j} + 2 \hat{k} and \vec{b} = 2 \hat{i} + \hat{k}

\vec{a} = \hat{j} - \hat{k} and \vec{b} = 2 \hat{i} + 3 \hat{j} - 2 \hat{k}

\vec{a} = 3 \hat{i} - \hat{j} + 2 \hat{k}

\vec{b} = 2 \hat{i} + \hat{j} - \hat{k},

(\vec{a} \times \vec{b}) \vec{a} .

If \vec{a} = 3 \hat{i} - \hat{j} - 2 \hat{k} and \vec{b} = 2 \hat{i} + 3 \hat{j} + \hat{k}, find (\vec{a} + 2 \vec{b}) \times (2 \vec{a} - \vec{b}) .

\vec{a} and \vec{b}

\vec{a} = \hat{i} - \hat{j} and \vec{b} = \hat{j} + \hat{k}

\vec{a} = 3 \hat{i} - 2 \hat{j} - 6 \hat{k} and \vec{b} = 4 \hat{i} - \hat{j} + 8 \hat{k}

\vec{a} = 2 \hat{i} - \hat{j} + 2 \hat{k} and \vec{b} = 4 \hat{i} + 4 \hat{j} - 2 \hat{k}

\vec{a} = 2 \hat{i} - 3 \hat{j} + \hat{k} and \vec{b} = \hat{i} + \hat{j} - 2 \hat{k}

\vec{a} = \hat{i} + 2 \hat{j} - \hat{k}, \vec{b} = \hat{i} - \hat{j} + \hat{k}

¯ ¯ ¯ a = 3 ¯ i - ¯ j - 2 ¯ ¯ ¯ k

¯ ¯ b = 2 ¯ i + 3 ¯ j + ¯ ¯ ¯ k

(¯ ¯ ¯ a + 2 ¯ ¯ b) \times (2 ¯ ¯ ¯ a - ¯ ¯ b) =

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