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Question

If (a+ib)5=α+iβ then (b+ia)5
is equal to

A
β - iα
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B
β + iα
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C
α+β
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D
-α-iβ
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Solution

The correct option is B β + iα


Solution: (a+ib)5=α+iβ
Taking complex conjugate
(aib)5=αiβ
(i2aib)5=αiβ
(i)5(b+ai)5=αiβ
(b+ai)5=αi+β
=α i+β


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