If a + ib is a root of the equation. x2 + x + 1 = 0, where a, b ∈ R and a ≠ 0, b ≠ 0, find the value of a.
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If a + ib is a root, the other root will be a - ib.
Sum of the roots = -1
⇒ a + ib + a - ib = -1
⇒ 2a = -1
⇒ a = (−1)2
If 3 - 5i is one root of the equation - x2 + ax + b = 0, find a + b, where a,b∈ R
Find the value of b, if one root of the equation x2 + ax + 2b = 0 is 2 + 4i, where a, b ∈ R