If A implies - B implies - C implies - D implies - then calculate the value of the expression 10 -152D38C32B8A20-

Consider the following two statements:
(A) Linear momentum of the system remains constant.
(B) Centre of mass of the system remains at rest.
(a) A implies B and B implies A.
(b) A does not imply B and B does not imply A.
(c) A implies B but B does not imply A.
(d) B implies A but A does not imply B.

Q. Consider the following two statements:
(A) Linear momentum of a system of particles is zero.
(B) Kinetic energy of a system of particles is zero.
(a) A implies B and B implies A.
(b) A does not imply B and B does not imply A.
(c) A implies B but B does not imply A.
(d) B implies A but A does not imply B.

Q. If a then b and if b then c

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If a then c.

Q. a - b - c implies

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If A implies ′+′,B implies ′−′,C implies ′×′,D implies ′÷′, then calculate the value of the expression 10 %(152D38C32B8A20).

The correct option is D 14D→÷ C→× B→− A→+(152D38C32B8A20)⇒152÷38×32−8+20 ⇒4×32−8+20 ⇒128−8+20 ⇒140 ⇒10 % 140=14 Option D is correct.

If A implies $^{'} +^{'}, B$ implies $^{'} -^{'}, C$ implies $^{'} \times^{'}, D$ implies $^{'} \div^{'}$ , then calculate the value of the expression $10 % (152 D 38 C 32 B 8 A 20)$ .

The correct option is D $14$
$D \to \div$
$C \to \times$
$B \to -$
$A \to +$

$(152 D 38 C 32 B 8 A 20)$
$\Rightarrow 152 \div 38 \times 32 - 8 + 20$
$\Rightarrow 4 \times 32 - 8 + 20$
$\Rightarrow 128 - 8 + 20$
$\Rightarrow 140$
$\Rightarrow 10 % 140 = 14$

Option D is correct.