If A is a 3rd order square diagonal matrix of non-positive entries such that A2=I, then
A
There may exist some diagonal element in A which is zero
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B
Value of |A| is −1
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C
A−1 does not exist
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D
|3adj(2A)|=1728
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Solution
The correct options are B Value of |A| is −1 D|3adj(2A)|=1728 If A is an involutor and diagonal matrix, then A2=I. Let A=⎡⎢⎣a000b000c⎤⎥⎦. Then A2=I ⇒|A|2=1⇒|A|=−1 {∵ entries are non-positive} Thus |A|=−1 A−1=A |2A|=−8 |3adj(2A)|=27.|adj(2A)|=27(−8)2=1728