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Question

If A is a 3×3 matrix such that |A|=5, then the value of |adj(4A)| is

A
163×52
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B
123×52
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C
163×62
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D
143×52
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Solution

The correct option is A 163×52
We know adj(kA)=kn1(adj(A)), kR
|adj(4A)|=|431adj A|
|adj(4A)|=|16adj(A)|
=163|adj A|
=163|A|n1
=163531
=163×52

Alternatively,
adj(kA)=|kA|n1
adj(4A)=|4A|2
adj(4A)=(43)2|A|2
adj(4A)=(42)3|A|2=(42)3×52

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