If A is a n×n non singular matrix Match List 1 with List 2, where k is a scalar
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Solution
By theory of matrices and determinants, we get |adjA|=|A|n−1 where A is n×n matrix. (AB)−1=B−1A−1 (kA)n Take k common from every row. Now there will n rows. Hence kn.An And A−1=adjA|A| Therefore adjA=|A|A−1