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B
A + I = 0
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C
A - I is non zero singular
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D
none of these
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Solution
The correct option is C A - I is non zero singular A2=I⇒A2−I=0 ⇒ (A+I)(A-I)=0 ∴ either |A+I|=0 or |A−I|=0 If |A−I|≠0, then (A+I)(A−I)=0⇒A+I=0 which is not so ∴|A−I| and A−I≠0.