If A is a point on the y-axis whose ordinate is 5 and B is the point (-3, 1), then the length of AB is

8 units

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5 units

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3 units

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None of these

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Solution

The correct option is A 5 units
$T h e p o i n t A i s o n Y - a x i s . ∴ i t s a b s c i s s a = 0. S o A = (x_{1}, y_{1}) = (0, 5) a n d B = (x_{2}, y_{2}) = (- 3, 1) [g i v e n] ∴ A B = \sqrt{({x_{2} - x_{1})}^{2} + {(y_{2} - y_{1})}^{2}} = \sqrt{{(- 3 - 0)}^{2} + {(1 - 5)}^{2}} = \sqrt{25} = 5 u n i t s . A n s O p t i o n B$

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P is a point on the -axis whose ordinate is 8. Q is a point on the line 8 – 3 – 8 = 0 whose abscissa is 4. Calculate the length of PQ.

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