If A is a singular matrix of order (nxn), then rank
(A) is,

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\leq n

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< n

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= n

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Solution

The correct option is C $< n$
Rank of square matrix is always less than or equal to order of matrix.
So, A is singular matrix. so, $| A | = 0$
$∴$ rank of $A \leq n$ .

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Similar questions

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If A is a singular matrix of order (nxn), then rank(A) is,

The correct option is C <n Rank of square matrix is always less than or equal to order of matrix.So, A is singular matrix. so, |A|=0∴ rank of A≤n.

If A is a singular matrix of order (nxn), then rank
(A) is,

The correct option is C $< n$
Rank of square matrix is always less than or equal to order of matrix.
So, A is singular matrix. so, $| A | = 0$
$∴$ rank of $A \leq n$ .