If A is a square matrix of order n and A=kB, where k is a scalar, then |A|=

$| B |$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$k | B |$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$k^{n} | B |$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$n | B |$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$k^{n} | B |$

$| A | = k^{n} | B |$ , by fundamental concept.

Suggest Corrections

Similar questions

Let A be a square matrix of order n and B be its adjoint, then for a scalar K, $| A B + K I_{n} |$ is ___

A

n^{t h}

B

| A B + K I_{n} |

K

d e t (k A) = k^{n} | A |

d e t (B) = k d e t (A) .

Let A be a square matrix of order n and B be its adjoint, then for a scalar K, $| A B + K I_{n} |$ is ___

Join BYJU'S Learning Program