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Question

If A is a square matrix such that A2=A, then write the value of 7A(I+A)3, where I is an identity matrix

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Solution

7A(I+A)3=7A(I3+A3+IA+AI)
=7A(I+A2×A+2IA)
=7A(I+A×A+2IA)[A2=A]
=7A(I+A2+2IA)
=7A(I+A+2IA)
=7AI+7A×A+14AIA
=7A+7A+14I(AA)
=14A+14IA
=14A+14A
=28A

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