If A is an acute angle and cosA=(5/13), then the value of cosec A is .........................
cosA=5/13 , We know, sin2A+cos2A = 1 ,
Lets take sinA = x , Also cosA = 5/13 , so cos2A= 25/169 then
Hence x2+ 25/169 = 1
x2= 1- 25/13 = 144/169
x = 12/13
now cosec A = 1/sinA
cosecA = 1/(12/13) = 13/12