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Question

If A is an acute angle and cosA=(5/13), then the value of cosec A is .........................

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Solution

cosA=5/13 , We know, sin2A+cos2A = 1 ,

Lets take sinA = x , Also cosA = 5/13 , so cos2A= 25/169 then

Hence x2+ 25/169 = 1

x2= 1- 25/13 = 144/169

x = 12/13

now cosec A = 1/sinA

cosecA = 1/(12/13) = 13/12


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