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Question

If A is an acute angle and SinA =cosA , find 3tan2A+ cos​​​​​​​​​​​​^2-1

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Solution

Since

Sin A = Cos A
Sin A = √1-Sin²A

Squaring both sides

Sin²A = 1- Sin²A
2Sin²A = 1
Sin²A = 1/2
Sin A = 1/√2
=> A = 45°

Therefore 3tan²A+ Cos²A - 1 = 3 x 1 + 1/2 - 1

= 5/2

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