If a is an acute angle and sina =√x−12x, find the value tan a.
√x+1x−1
√x2−1
√x2+1
cos2a+sin2a=1 cos2a=1−x−12x=2x−x+12x=x+12x cosa=√x+12x, becuase a is an acute angle. tana=sinacosa=√x−1x+1
The simplest form of (x3–1)(x2–1) is