If 'A' is an acute angle and tan A + cot A = 2 then find the value of tan^9 A + cot^7 A.

Open in App

Solution

Suggest Corrections

Similar questions

θ

tan θ + cot θ = 2

{tan}^{7} θ + {cot}^{7} θ

tan 2 A = cot (A - 60^{\circ}),

tan 2 A = cot (A - 18)

2 A

A

If $θ$ is an acute angle and $t a n θ + c o t θ = 2$ , then find the value of $t a n^{7} θ + c o t^{7} θ$ .

t a n 2 A = c o t (A - 18^{\circ})

Join BYJU'S Learning Program