If a is an even integer and b is an odd integer, which of the following must be even?

a b + 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a^{2} + 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a^{2} + b^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

b^{2} + 3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $b^{2} + 3$
Given $a$ + even and $b$ = odd. then
$a b + 1$ = even $\times$ odd $+$ odd $=$ even $+$ odd $=$ odd.

$a^{2} + 3 =$ even $+$ odd $=$ odd
$a^{2} + b^{2} =$ even $+$ odd $=$ odd.

$b^{2} + 3 =$ odd $+$ odd $=$ even.
Therefore the correct option is $D$ .

Suggest Corrections

Similar questions

x

2 x

2 x

x

n

n

2 n, 3 n, 3 n + 1, 3 n - 5, 4 n + 1

a

b

x a n d y a r e i n t e g e r s a n d i f

\frac{x^{2}}{y^{3}}

i s e v e n i n t e g e r t h e n w h i c h o f t h e f o l l o w i n g

m u s t b e a n e v e n i n t e g e r ?

Join BYJU'S Learning Program