You visited us 3 times! Enjoying our articles? Unlock Full Access!

Adjoint of a Matrix

If A is an ...

Question

If $A$ is an invertible matrix. then which of the followings are true:

A \neq 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Adj.

A \neq 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

| A | \neq 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

A^{- 1} = | A | A d j . A .

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A Adj. $A \neq 0$
B $A \neq 0$
D $| A | \neq 0$
A is invertible matrix
$\Rightarrow A^{- 1}$ exists
$\Rightarrow | A | \neq 0$
$A d j A \neq 0$
$A \neq 0$
Option A, B, C are correct

Suggest Corrections

Similar questions

{(A^{2})}^{- 1} = {(A^{- 1})}^{2}

|A^{- 1}| = {|A|}^{- 1}

{(A^{T})}^{- 1} = {(A^{- 1})}^{T}

|A| \neq 0

A = ⎡ ⎢ ⎣ \begin{matrix} 2 & 1 & 1 0 & 1 & 1 1 & 1 & 2 \end{matrix} ⎤ ⎥ ⎦

x^{3} - 5 x^{2} + 7 x - 3 = 0

A

A

a_{0} x^{n} + a_{1} x^{n - 1} + . . . a_{n - 1} x + a_{n} = 0

a_{n} \neq 0

A

A

A (a d j A) = [\begin{matrix} 10 & 0 0 & 10 \end{matrix}]

| A | =

Join BYJU'S Learning Program