If a is any real number,the number of roots of cot x =a in the first quadrant is (are).
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Given:cot x−tan x=a⇒1tan x−tan x=a⇒1−tan2x=a tan x⇒tan2 x+a tan x−1=0It is a quadratic equation.If tan x=z,then the equation becomesz2+az−1=0⇒z=−a±√a2+42⇒tan x=−a±√a2+42⇒x=tan−1(−a±√a2+42)There are two roots of the given equation,but we need to find the number of roots in the first quadrant.that is exactly one root of the equation,that is ,x=tan−1 (−a±√a2+42)