If $A$ is any square matrix of order $2$ , then $a d j (a d j A)$ =

A

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det A

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A^{- 1}

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None of these

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Solution

The correct option is A $A$
We know that
$a d j (a d j A) = | A |^{n - 2} A$
So, here $a d j (a d j A) = | A |^{0} A$
$\Rightarrow a d j (a d j A) = A$

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