If A is matrix of order 3, such that A(adjA)=10I, then |adj A|=
A
10
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B
10I
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C
1
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D
100
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Solution
The correct option is D100 Consider the following identity A(adjA)=|A|I. Thus comparing it with the above equation gives us |A|=10 Now |adjA|=|A|n−1 where n is the order of the square matrix. Here 'n' is 3, therefore, |adjA|=|A|3−1=|A|2=102=100.