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Question

If a is the A.M of two numbers b and c and G1,G2 are two Geometric means between b and c,then the value of G31+G32

A
3abc
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B
2abc
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C
4abc
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D
None of these
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Solution

The correct option is B 2abc
Given that, 2a=b+c
and b,G1,G2,c are in G.P.
Therefore, G12=bG2 ....(1)
G13=bG2G1
and G22=cG1 ....(2)
G23=cG1G2

Multiplying (1) & (2), we get
G1G2=bc ...(3)
Therefore, G31+G32=bG2G1+cG2G1=G2G1(b+c)
G31+G32=2abc ....[ From (3) ]
Ans: B

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