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Question

If a is the degree of dissociation of K4[Fe(CN6)] than an abnormal mass of complex in the solution will be:

A
Mnormal(1+2a)1
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B
Mnormal(1+3a)1
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C
Mnormal(1+a)1
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D
Mnormal(1+4a)1
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Solution

The correct option is C Mnormal(1+4a)1
Solution:- (D) Mnormal(1+4a)1
Dissociation of K4[Fe(CN)6]-
InitiallyAfter dissociationK4[Fe(CN)6]11a4K+04a+[Fe(CN)6]0a
Van't hoff factor = Total moles after dissociation =(1a)+4a+a=1+4a
As we know that,
i=Normal molar massAbnormal molar mass
Abnormal molar mass=Normal molar massi
Abnormal molar mass =Mnormal1+4a
Abnormal molar mass =Mnormal(1+4a)1
Hence the abnormal molar mass of K4[Fe(CN)6] is Mnormal(1+4a)1.

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