You visited us 1 times! Enjoying our articles? Unlock Full Access!

Arrhenius Acid

If 'a' is t...

Question

If $^{'} a^{'}$ is the fraction of $N_{2} O_{4}$ molecules dissociated in the reaction $(N_{2} O_{4} ⇌ 2 N O_{2})$ , then at equilibrium, the total number of moles of $N_{2} O_{4}$ and $N O_{2}$ present will be:

a

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 + a

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 a

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 - a

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $1 + a$
$N_{2} O_{4} ⇋ 2 N O_{2}$
At Eq. $1 - a$ $2 a$

Total moles $= 1 - a + 2 a = 1 + a$

Suggest Corrections

Similar questions

a

N_{2} O_{4} ⇌ 2 {N O}_{2}

N_{2} O_{4} ⇌ 2 {N O}_{2}

N_{2} O_{4}

{N O}_{2}

N_{2} O_{4} ⇌ 2 N O_{2}

a

N_{2} O_{4}

N_{2} O_{4}

N_{2} O_{4} ⇌ 2 N O_{2}

55^{\circ} C

%

N_{2} O_{4}

50.3 %

P

N_{2} O_{4} : N O_{2}

1 : 8

N_{2} O_{4} ⇋ 2 N O_{2}

x

N_{2} O_{4}

N_{2} O

N O_{2}

280^{\circ} C

0.2 m o l

N_{2} O_{4}

2 \times 10^{- 3}

N O_{2}

2 L

N_{2} O_{4} ⇌ 2 N O_{2}

Join BYJU'S Learning Program