Question

If ${}^{\prime }{a}^{\prime }$ is the number of lines of symmetry and ${}^{\prime }{b}^{\prime }$ is the order of rotational symmetry for the figure shown below, then find the value of (b-a).

Answer 1

This figure does not have any line of symmetry. Hence $a=0$. The figure looks same 6 times while rotating about its centre around ${360}^{\circ }$, so the order of rotation is 6. Hence $b=6$.
Therefore, $b-a=6$.