Question

If a is the rake angle of a cutting tool, $\varphi$ is the shear angle, then the ratio of velocity of chip to the shear velocity is given by

• A. $\frac{\sin \varphi }{\cos \alpha }$
• B. $\frac{\cos (\varphi -\alpha )}{\cos \alpha }$
• C. $\frac{\sin \varphi }{\cos (\varphi -\alpha )}$
• D. $\frac{\cos \alpha }{\sin \varphi }$

Answer 1

The correct option is A $\frac{\sin \varphi }{\cos \alpha }$

$\frac{V_C}{V_S}=\frac{\sin \varphi }{\cos \alpha }$

$\frac{V}{\cos (\varphi -\alpha )}=\frac{V_C}{\sin \varphi }=\frac{V_S}{\cos \alpha }$