Question

If $A$ is the set of the divisors of $15,B$ is the set of prime numbers less than $10$ and $C$ is the set of even natural numbers smaller than $9,$ then $(A\cup C)\cap B$ is the set

• A. $\{1,3,5\}$
• B. $\{1,2,3\}$
• C. $\{2,3,5\}$
• D. $\{2,5\}$

Answer 1

The correct option is C $\{2,3,5\}$

$A=\{1,3,5,15\}$
$B=\{2,3,5,7\}$
$C=\{2,4,6,8\}$
Hence, $(A\cup C)\cap B=\{2,3,5\}$