Question

If 'a' is x % more than 'b' and 'b' is y % less than 'a'. then the relation between x and y is

• A. $\frac{1}{x}+\frac{1}{y}=\frac{1}{100}$
• B. $\frac{1}{y}-\frac{1}{x}=\frac{1}{100}$
• C. $\frac{1}{x}-\frac{1}{y}=100$
• D. $\frac{1}{y}-\frac{1}{x}=100$

Answer 1

Answer: (B)

$\frac{1}{y}-\frac{1}{x}=\frac{1}{100}$

$y\%=\frac{100\times x}{100+x}\%$

$\Rightarrow y=\frac{100\times x}{100+x}$

$\Rightarrow \frac{1}{y}=\frac{100+x}{100\times x}=\frac{1}{x}=\frac{1}{100}$

$\Rightarrow \frac{1}{y}-\frac{1}{x}=\frac{1}{100}$