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Question

If Ak=0 for some value of k and B=1+A+A2+...+Ak1, then B1 equal

A
IA
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B
I+A
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C
IAk1
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D
None of these
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Solution

The correct option is A IA
Let B=I+A+A2+A3+...+Ak1
B(IA)=(I+A+A2+...+Ak1)(IA)
=IA+AA2+A2+...+Ak1Ak=I=Ak=I(Ak=O)
Hence, (IA)1=I+A+A2+...+Ak1=B
B1=IA

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