Question

If a leap year is selected at random, what is the chance it will contain 53 Sunday?

• A. probability is $\frac{4}{7}$
• B. probability is $\frac{3}{7}$
• C. probability is $\frac{2}{7}$
• D. none of these

Answer 1

The correct option is C probability is $\frac{2}{7}$

A leap year has $52$ full weeks and $2$ other days.
So,the possibilities for the other $2$ days are : $(sat,sun),(sun,mon),(mon,tue),(tue,wed),(wed,thu),(thu,fri),(fri,sat)$
So,$n\left(S\right)=7$ and $n\left(E\right)=2$
Hence,probability of having $53$ sundays in a leap year is $2/7$.