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Byju's Answer
Standard X
Mathematics
Theoretical Probability
If a leap yea...
Question
If a leap year is selected at random what is the probability that it will contain
53
Tuesdays?
A
1
7
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B
2
7
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C
3
7
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D
4
7
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Solution
The correct option is
C
2
7
1
y
e
a
r
=
365
days
A leap year has
366
days
A year has
52
weeks. Hence there will be 52 Tuesdays for sure.
52
w
e
e
k
s
=
52
×
7
=
364
d
a
y
s
366
–
364
=
2
days
In a leap year there will be 52 Tuesdays and 2 days will be left.
These 2 days can be:
Sunday, Monday
Monday, Tuesday
Tuesday, Wednesday
Wednesday, Thursday
Thursday, Friday
Friday, Saturday
Saturday, Sunday
Of these total 7 outcomes, the favorable outcomes are 2.
Hence the probability of getting 53 Tuesdays in a leap year
P
(
E
)
=
2
7
Suggest Corrections
1
Similar questions
Q.
Assertion :If a non leap year is selected at random then, the probability it will contains 53 Monday is
1
7
. Reason: A non leap year has 365 days
Q.
The probability that a leap year will have 53 Fridays or 53 Saturdays is
(a) 2/7
(b) 3/7
(c) 4/7
(d) 1/7
Q.
Find the probability that a leap year selected at random will contain
53
Tuesdays.
Q.
Question 19
The probability that a non-leap your selected at random will contains 53 Sunday is
(a)
1
7
(b)
2
7
(c)
3
7
(d)
5
7
Q.
If a leap year is selected at random, what is the chance that it will contain 53 tuesdays ?
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