You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equal Sets

If A = 0 , ...

Question

If $A = {0}, B = {x : x > 15 a n d x < 5}, C = {x : x - 5 = 0}, D = {x : x^{2} = 25}$ , E = { x : x is a positive integer root of equation $x^{2} - 2 x - 15 = 0$ } , then pair of equal sets is :

A, B

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B, C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B, C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C, E

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $C, E$
Option (D) is correct , as in tabular form the set C = {5} and set E = {5}
So, , C = E
Pair of equal sets is C and E

Suggest Corrections

Similar questions

List all the elements of the following sets :

(i) A = { $x : x^{2} < - - 10, x ϵ Z$ }

(ii) B = { $x : x = \frac{1}{2 n - 1}, 1 < - - n < - - 5$ }

(iii) { $C = x : x is an integer, - \frac{1}{2} < x < \frac{9}{2}$ }

(iv) D = {x : x is a vowel in the word "EQUATION"}

(v) E = {x : x is a month of a year not having 31 days}

(vi) F = {x : x is a letter of the word "MISSISSIPPI" }

A = \{x : x^{2} \leq 10, x \in Z\}

B = \{x : x = \frac{1}{2 n - 1}, 1 \leq n \leq 5\}

C = \{x : x is an integer, - \frac{1}{2} < x < \frac{9}{2}\}

x^{2}

x^{2}

A = {0}, B = {x : x > 15 and x < 5}

C = {x : x - 5 = 0}, D = {x : x^{2} = 25}

E = {x : x

x^{2} - 2 x - 15 = 0}

Join BYJU'S Learning Program