A∩C={1}B∩D={2}(A∩C)×(B∩D)={(1,2)} ...(2)
from (1) and (2)
(A∩B)×(C∩D)=(A∩C)×(B∩D)
(ii)(A×B)∪(C×D)={(1,1),(1,2),(1,3),(1,4),(1,7),(2,1),(2,2),(2,3),(5,2),(5,4),(5,7),(7,2),(7,4),(7,7)}
(A∪C)={1,2,5,7}
(B∪D)={1,2,3,4,7}
(A∪C)×(B∪D)={(1,1),(1,2),(1,3),(1,4),(1,7),(2,1),(2,2),(2,3),(2,4),(2,7),(5,1),(5,2),(5,3),(5,4),(5,7),(7,1),(7,2),(7,3),(7,4),(7,7)}
∴(A×B)∪(C×D)≤(A∪C)×(B∪D)